Question

find the domain of the function f/g(x) given f(x)=x^2+2x-8 and g(x)=x^2-16

Answer 1

Answer:

C) $\{x|x\neq-4 \:or \:4\}$

Step-by-step explanation:

$\frac{x^2+2x-8}{x^2-16}\\ \\\frac{(x+4)(x-2)}{(x+4)(x-4)}\\ \\x\neq-4 \:or \:4$

Here, $x\neq-4$ is a hole on the graph since $x+4$ exists in both the numerator and denominator.