Question

Maggie puts together two isosceles triangles so that they share a base, creating a kite. Each leg of the upper triangle measures 41 inches and each leg of the lower one measures 50 inches. A kite with diagonals is shown. It has side lengths of 41, 41, 50, and 50. The distance from the left point to the intersection is 40 and the distance from the right point to the intersection is 40. If the length of the base of both triangles measures 80 inches, what is the length of the kite’s shorter diagonal? 30 inches 39 inches 10 StartRoot 39 EndRoot inches 10 StartRoot 11 EndRoot inches.

Answer 1

The length of another diagonal length is 39 inches.

Geometry

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

Kite shape

It is a polygon that has four sides and four corners. The sum of the internal angle is 360 degrees. In Kite, the pair of adjacent sides are equal. And its diagonals intersect at a right angle.

Given

A kite with diagonals is shown. It has side lengths of 41, 41, 50, and 50.

One diagonal length is 80 inches.

To find

The length of another diagonal length.

How to find the length of another diagonal length?

We know that its diagonals intersect at a right angle.

Then according to Pythagoras theorem

For ΔAED

H² = P² + B²

41² = P² + 40²

P = 9

Similarly,

For ΔCED

H² = P² + B²

50² = P² + 40²

P = 30

The length of another diagonal length will be

30 + 9 = 39

Thus, the length of another diagonal length is 39 inches.

More about the geometry link is given below.

https://brainly.com/question/7558603

Answer 2

Answer:

39 units

Step-by-step explanation:

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