The mass percent of hydrogen in CH₄O is 12.5%.
Mass percent is the mass of the element divided by the mass of the compound or solute.
mCH₄O = 1 mC + 4 mH + 1 mO = 1 (12.01 amu) + 4 (1.00 amu) + 1 (16.00 amu) = 32.01 amu
mH in mCH₄O = 4 mH = 4 (1.00 amu) = 4.00 amu
%H = (mH in mCH₄O / mCH₄O) × 100%
%H = 4.00 amu / 32.01 amu × 100% = 12.5%
The mass percent of hydrogen in CH₄O is 12.5%.
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