Question

joe has a handful of dimes and quarters that values to $5.30. He has one fewer than twice as many dimes than quarters. How many of each coin does he have?

Answer 1

Answer:

12 quarters 23 dimes

Step-by-step explanation:

x(0.25)+(2x-1)(0.10)=5.30

0.25x+0.2x-0.10=5.30

0.45x=5.40

x=12

12 quarters

12(2)=24-1=23 dimes