Question

Inside a television picture tube there is a build-up of electrons (charge of 1. 602 × 10–19 C) with an average spacing of 38. 0 nanometers between electrons. Find the electric field inside the picture tube. (Round to three significant figures. ).

Answer 1

The magnitude of the electric field inside the picture tube is 998.476 kN/C.

What is an electric field?

It is an area in the space where a charged particle experiences a force. It can be calculated by the formula,

$E =\dfrac {kQ}{r^2 }$

Where,

$E$ = electric field produced

$Q$ = charge =  $1.602 \times 10^{-19}\rm \ C$

$r$ = distance = $38 \times 10^{-9}\rm \ m$

$k$ = Coulomb's constant = $9 \times 10^9 \rm \ N. m2 / C2$

Put the values in the formula,

$E = \dfrac {9 \times 10^9\times 1.602 \times 10^{-19}}{(38 \times 10^{-9})^2}\\\\E = 998.476 \rm \ kN/C$

Therefore, the magnitude of the electric field inside the picture tube is 998.476 kN/C.

Learn more about the electric field:

https://brainly.com/question/3783640

Answer 2

Answer:

997,000 N/C

Explanation:

E2020