Question

Point C is located at (1, 2), and point D is located at (−4, −2). Find the x value for the point that is 1 over 4 the distance from point C to point D. −0. 25 −1. 5 −2. 75 −4.

Answer 1

The distance from point C to point D is -0.25.

Given

Point C is located at (1, 2) and point D is located at (−4, −2).

Let Coordinates of A= (x, y)

A point is located 1/4 the distance from C to D.

So the remaining distance from point A to D is 3/4

Thus the ratio of CA : AD = m :n = 1: 3

What is the section formula?

When point C divides a segment AB in the ratio m:n, we use the section formula to find the coordinates of that point.

$\rm Distance \ from \ point \ C\ to \ D = \dfrac{mx_1+nx_2}{m+n}\\\\ Distance \ from \ point \ C\ to \ D = \dfrac{1(-4)+3(1)}{1+3}\\\\ Distance \ from \ point \ C\ to \ D = \dfrac{-4+3}{5}\\\\ Distance \ from \ point \ C\ to \ D = \dfrac{-1}{5}\\\\ Distance \ from \ point \ C\ to \ D = -0.25$

Hence, the distance from point C to point D is -0.25.

To know more about the Section formula click the link given below.

https://brainly.com/question/26239726