Question

The means of six number = 41

Three numbers are 32 , 31 , 42

other three are a,a,a

What sum of 6 numbers

find value of A?

Answer 1

$\qquad\huge \rm༆ Answer ༄$

Let's use the formula to fund mean here ~

$\boxed{ \sf mean = \frac{sum \: of \: all \: terms}{number \: of \: terms} }$

That is ;

$\qquad \sf  \dashrightarrow \: 41 = \dfrac{32 + 31 + 42 + a + a + a}{6}$

$\qquad \sf  \dashrightarrow \: (41 \times 6) = 105 + 3a$

$\qquad \sf  \dashrightarrow \: 246 = 105 + 3a$

$\qquad \sf  \dashrightarrow \: 3a = 246 - 105$

$\qquad \sf  \dashrightarrow \: 3a = 141$

$\qquad \sf  \dashrightarrow \: a = 141 \div 3$

$\qquad \sf  \dashrightarrow \: a = 47$

Therefore the value of a is 47