Question

A population is solely comprised of 72 A2A2 individuals. 10 A1A1 individuals migrate in and contribute to the mating pool. What is the frequency of A1A2 individuals in the offspring? Answer to 2 decimal places. Hint: Use the Gene Flow table!

Answer 1

We have that the the frequency of A1A2 individuals in the offspring is mathematically given as

2pq = 0.65

Frequency

Generally the equation for the Hardy-Weinberg equilibrium   is mathematically given as

$(P+q)^2=p^2+2pq+q^2\\\\(P+q)^2=1$

Therefore

q2= the frequency of individual Al Al

$q2= (72/10+72) \\\\q2= 72/82$

thus,

P = [10/82]^(1/2)

q= [72/82]^(1/2)

Hence

2pq = 0.65

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