Question

A student produced 1.06 g of NH3 from the reaction of 1.77 g of H2 with 25.7g N2 gas.
N2 + 3H2 → 2NH3

Theoretical yield?

Percent yield?

Answer 1

The theoretical yield of NH3 is 10.03 g and percent yield is 10.56%

What is the theoretical yield?

The theoretical yield is obtained from the eequation if reaction.

The equation of the reaction is given below:

• N2 + 3H2 → 2NH3

moles of reactants and products:

moles of H2 = 1.77/2 = 0.885 moles

moles of N2 = 25.7/28 = 0.918 moles

moles of NH3 = 1.06/17 = 0.062

From the equation of the reaction, H2 is the limiting reactant

3 moles of H2 produces 2 moles of NH3

0.885 moles of H2 will produce 2/3 × 0.918 = 0.59 moles of NH3

Therefore:

theoretical yield = 0.59 × 17

theoreticalyield = 10.03 g of NH3

Percent yield = 1.06/10.03 × 100%

percent yield = 10.56%

Therefore, the theoretical yield is 10.03 g and percent yield is 10.56%.

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