There are 2.223 moles of ions contained in 1.27 L of a 1.75 M solution of Mg(NO3)2.
HOW TO CALCULATE NUMBER OF MOLES:
- The number of moles of an ion can be calculated by multiplying the molarity by the volume of the solution. That is:
No. of moles = molarity × volume
- According to this question, 1.27 L is contained in a 1.75 M solution of Mg(NO3)2. The number of moles is calculated as follows:
no. of moles = 1.75M × 1.27L
no. of moles = 2.223mol
Therefore, there are 2.223 moles of ions contained in 1.27 L of a 1.75 M solution of Mg(NO3)2.
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