A race car completes the final lap of a race on a 2-kilometer circular track. At the start of the lap, it crosses the line at 60 meters/second. It completes the lap 28. 57 seconds later, crossing the line at 85 meters/second. Calculate the displacement and average acceleration of the car along the track over the course of the final lap. A. Displacement is 0 meters, and acceleration is 0. 88 meters/second2. B. Displacement is 2,000 meters, and acceleration is 1. 14 meters/second2. C. Displacement is 0 meters, and acceleration is 70. 0 meters/second2. D. Displacement is 2,000 meters, and acceleration is 80. 0 meters/second2. E. Displacement is 0 meters, and acceleration is 0. 70 meters/second2.

Displacement can be defined as the overall distance traveled by an object or length of a strait line between final and initial position of the object.

Average acceleration:

It can be fined as the overall change in velocity of the object in given time. It can be given as:

[tex]a_{avg} = \dfrac {v_f- v_i}{t}[/tex]

Where,

[tex]v_f[/tex] - final velocity

[tex]v_i[/tex] - initial velocity

[tex]t[/tex] - time

Put the values in the formula,

[tex]a_{avg}= \dfrac {(85 {\rm \ m/s} - 60{\rm \ m/s}}{8.57 {\rm \ s}} \\\\a_{avg}= 0.88 {\rm \ m/s^2}[/tex]

Therefore, the average acceleration of the car is 0.88 m/s² but the displacement of the car is zero because the initial final position is the same.

Learn more about acceleration:

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