What is the general form of the equation of a circle with center at (a, b) and radius of length m? A. X2 y2 − 2ax − 2by (a2 b2 − m2) = 0 B. X2 y2 2ax 2by (a2 b2 − m2) = 0 C. X2 y2 − 2ax − 2by (a b − m2) = 0 D. X2 y2 2ax 2by a2 b2 = -m2.

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31-01-2022
Mathematics

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What is the general form of the equation of a circle with center at (a, b) and radius of length m? A. X2 y2 − 2ax − 2by (a2 b2 − m2) = 0 B. X2 y2 2ax 2by (a2 b2 − m2) = 0 C. X2 y2 − 2ax − 2by (a b − m2) = 0 D. X2 y2 2ax 2by a2 b2 = -m2.

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ap8997154 ap8997154 · Answer 1 · 2022-02-10T12:35:57+01:00

The general form of the equation of a circle with center at (a, b) and radius of length m is written as [tex](x-a)^2+(y-b)^2 = m^2[/tex].

What is the general form of the equation of a circle?

The general form of the equation of a circle is written as,

[tex](x-h)^2+(y-k)^2 = R^2[/tex]

where (h, k) is the coordinates of the center of the circle, while R is the radius of the circle.

Equation of circle with center at (a, b) and radius of length m

We have already discussed the general form of the equation of a circle, substituting the values into it,

[tex](x-h)^2+(y-k)^2 = R^2\\\\(x-a)^2+(y-b)^2 = m^2[/tex]

Hence, the general form of the equation of a circle with center at (a, b) and radius of length m is written as [tex](x-a)^2+(y-b)^2 = m^2[/tex].

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