Question

Which of the following contains the fewest atoms? you shouldn't need to do a calculation here.

Answer 1

The one that contains the fewest atoms is Rb or Rubidium.

How do you calculate the number of atoms?

The number of atoms can be calculated using the following formula:

• mass of the substance/ atomic mass units (AMU) x Avogrado's number

Now, let's calculate the mass for all the elements:

• 4.0 g Li
• 4.0g Li/ 6.94 g/mol x  6.02  10²³
• 0.57 x  6.02 x 10²³
• 3.43 x 10²³

• 4.0 g Na
• 4.0g Na/ 22.98 g/mol x  6.02  10²³
• 0.17  x 6.02 x10²³
• 1.02 x 10²³

• 4.0 g Rb
• 4.0 g Rb/ 85.46 g/mol x  6.02  10²³
• 0.04 x 6.02 x 10²³
• 2.4 x 10²²

• 4.0 g Ca
• 4.0 g Ca / 40.07 g/mol x  6.02  10²³
• 0.09x 6.02 x 10²³
• 5.41 × 6.02²²

From these options, the lowest number is 2.4 x 10²² which refers to Rubidium. and therefore, this is the option with the least atoms.

Note: This question is incomplete because the options are missing; here are the options:

A) 4.0 g Li

B) 4.0 g Na

C) 4.0 g Rb

D) 4.0 g K

E) 4.0 g Ca

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