Question

A circle is circumscribed about an equilateral triangle with side lengths of $9$ units each. What is the area of the circle, in square units

Answer 1

Using it's formula, it is found that the area of the circle, in square units, is of $27\pi$.

What is the area of a circle circumscribed about an equilateral triangle?

Considering that the equilateral triangle has side length l, the area of the circle is given by:

$A = \frac{\pi l^2}{3}$

In this problem, the sides have lengths of 9 units each, hence l = 9 and:

$A = \frac{\pi 9^2}{3} = 27\pi$

The area of the circle, in square units, is of $27\pi$.

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