Question

At which values of x does the function F(x) have a vertical asymptote? Check
all that apply. F(x)=3/x(x-5)(x+1)

Answer 1

Answer:

B, E, and F

Step-by-step explanation:

A rational function has vertical asymptotes where its denominator is equal to 0. Thus $0=x(x-5)(x+1)$ has the solutions $x=0$, $x=5$, and $x=-1$.

Answer 2

The function F(x) = 3/[x(x-5)(x+1)] have a vertical asymptote at x = 0 , x= 5 and x = -1 hence, correct option is (B) , (E) and (F).

What is a vertical asymptote?

A vertical line with either of the following characteristics is said to have a vertical asymptote 1.

The functional approaches infinity when approaching from either the favorable or unfavorable side.

A vertical asymptote is a line that directs the function's graph but is not obviously a part of this.

Given that the  F(x) = 3/[x(x-5)(x+1)] for vertical asymptote the denominator should be zero.

x(x-5)(x+1) = 0

so ether x will be zero or x -5 or x +1 or any two or all three.

x = 0 , x= 5 , x = -1 hence the option (B) , (E) and (F) will be the correct answer.

For more information about the  vertical asymptote

https://brainly.com/question/4084552

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