Question

Eighteen percent of apples grown in an orchard have defects. Let X = the number of apples that are randomly inspected from the orchard until a defective one is found.

What is P(X ≤ 4)?

Round to 3 decimal places.

Answer 1

Answer:

0.219 or 21.028%

Step-by-step explanation:

0.18 are defective, so

P(x=1) = 0.18

P(x=2) = 0.18^2 = 0.0324

P(x=3) = 0.18^3 = 0.005832

P(x=4) = 0.18^4 = 0.00104976

Then add them together: 0.21928176