Question

The sum of two polynomials is –yz2 – 3z2 – 4y 4. If one of the polynomials is y – 4yz2 – 3, what is the other polynomial? –2yz2 – 4y 7 –2yz2 – 3y 1 –5yz2 3z2 – 3y 1 3yz2 – 3z2 – 5y 7.

Answer 1

The other polynomial is $\rm 3yz^2-3z^2-5y+7$.

Given

The sum of two polynomials is $\rm -yz^2-3z^2 -4y+ 4$. If one of the polynomials is $\rm y -4yz^2 - 3.$

How to find the sum of two polynomials?

The sum of two polynomial is given by;

$\rm Sum \ of \ polynomial = First \ polynomial + Second \ polynomial$

Therefore,

The other polynomial is;

$\rm Sum \ of \ polynomial = First \ polynomial + Second \ polynomial\\\\ \rm -yz^2-3z^2 -4y+ 4=\rm y -4yz^2 - 3+ Second \ polynomial\\\\ Second \ polynomial= -yz^2-3z^2 -4y+ 4-y+4yz^2+3\\\\Second \ polynomial =3yz^2-3z^2-5y+7$

Hence, the other polynomial is $\rm 3yz^2-3z^2-5y+7$.

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Answer 2

Answer:

Its D

Step-by-step explanation:

i hope this helps :,)