Question

6. Check your understanding; Use the equation for acceleration to determine the acceleration for
the following two motions

Answer 1

Answer:

#A

• Initial=u=0m/s
• Final=8m/s=v
• Time=4s=t

Acceleration=a

$\\ \tt\hookrightarrow a=\dfrac{v-u}{t}=\dfrac{8}{4}=2m/s^2$

#B

• Initial=u=8m/s
• Final=v=0m/s
• Time=4s=t

$\\ \tt\hookrightarrow a=\dfrac{0-8}{4}=\dfrac{-8}{4}=-2m/s^2$

Answer 2

Answer(s):

• Practice A: 2 m/s
• Practice B: -2 m/s

Solution for Practice-A:

We know that:

• Formula: Acceleration = v₁ - v₂/t
• v₁ = Final velocity
• v₂ = Starting velocity
• t = Time

Solution:

• v₁ - v₂/t
• => 8 - 0/4
• => 8/4
• => 2/1
• => 2 m/s

Hence, the acceleration is 2 m/s for practice A.

Solution for Practice B:

We know that:

• Formula: Acceleration = v₁ - v₂/t
• v₁ = Final velocity
• v₂ = Starting velocity
• t = Time

Solution:

• v₁ - v₂/t
• => 0 - 8/4
• => -8/4
• => -2/1
• => -2 m/s

Hence, the acceleration is -2 m/s for practice B.

Hoped this helped!