Question

state the value of
$\tan(60°) + \cot(60°)$
rationalise the denominator if needed !

thankyou ~​

Answer 1

Answer:

$tan(60)+cot60)\\\sqrt{3} +\frac{1}{\sqrt{3} } \\\frac{3+1}{\sqrt{3} } \\\frac{4}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } \\\frac{4\sqrt{3} }{3}$

Hope it will help you a lot.

Step-by-step explanation:

Answer 2

Answer:

$\dfrac{4\sqrt3}{3}$

Step-by-step explanation:

$\pink{\frak{Given }}\Bigg\{ \sf \tan(60^o) + \cot(60^o)$

And we need to find out the value of given expression . As we know that the value of ,

$\sf \longrightarrow tan 60^o = \sqrt3$

And ,

$\sf \longrightarrow cot 60^o = \dfrac{1}{tan60^o}=\dfrac{1}{\sqrt3}$

Substituting the values in the given expression ,

$\sf \longrightarrow tan 60^o + cot 60^o$

$\sf \longrightarrow \sqrt3 +\dfrac{1}{\sqrt3}$

Take LCM as √3 and simplify ,

$\sf \longrightarrow \dfrac{(\sqrt3)(\sqrt3) +1}{\sqrt3}$

Simplify ,

$\sf \longrightarrow \dfrac{3+1}{\sqrt3}=\dfrac{4}{\sqrt3}$

Rationalize the denominator by multiplying numerator and denominator by √3 .

$\sf \longrightarrow \dfrac{(4)(\sqrt3)}{(\sqrt3)(\sqrt3)}$

Simplify by multiplying ,

$\sf \longrightarrow \boxed{\bf \dfrac{4\sqrt3}{3}}$