Question

Find the area and perimeter of a TV set with dimensions 88 cm x 49 cm (to nearest cm). (Hint: find the upper and lower bounds to find the area and perimeter)​

Answer 1

Answer:

Given below.

Step-by-step explanation:

For upper bound, the length is 88.5 cm and width is 49.5 cm

So, area of rectangle, TV = length * width

                                          =  88.5  *  49.5

                                          = 4380.75 cm²

So, perimeter =  2( length + width )

                       = 2( 88.5 + 49.5 )

                        = 276 cm

For lower bound, the length is 87.5 cm and width is 48.5 cm

So, area of rectangle, TV = length * width

                                          =   87.5 *  48.5

                                          = 4243.75 cm²

So, perimeter =  2( length + width )

                       = 2(  87.5 + 48.5 )

                        = 272 cm

Answer 2

Here

• Length=L=88cm
• Breadth=49cm=B

Note the formulas

$\boxed{\bf Perimeter=2(L+B)}$

$\boxed{\bf Area=LB}$

Now

$\\ \tt\hookrightarrow Perimeter=2(88+49)=2(137)=274cm$

$\\ \tt\hookrightarrow Area=88(49)=4312cm^2$