Answer:
9.72s
Explanation:
[tex]\pink{\frak{Given}}\begin{cases}\textsf{ A car starts from rest.}\\\textsf{It has an acceleration of 2m/s$^2$.}\\\textsf{ The final velocity of the car is 70km/hr.}\end{cases}[/tex]
Here we need to find out the time that the car took to achieve the velocity of 70km/hr after starting from rest . Firstly convert the final velocity in m/s by multiplying it by 5/18 , as ,
[tex]\longrightarrow\sf 70km/hr = 70 \times \dfrac{5}{18} m/s =\bf 19.44\ m/s [/tex]
[tex]\longrightarrow\sf a =\dfrac{v - u}{t} [/tex]
Plug in the respective values ,
[tex]\longrightarrow\sf 2m/s^2 = \dfrac{ 19.4 m/s -0m/s}{t} \\ [/tex]
Simplify ,
[tex]\longrightarrow\sf 2m/s^2 =\dfrac{19.4m/s}{t} [/tex]
Cross multiply ,
[tex]\longrightarrow\sf t = \dfrac{19.44m/s}{2m/s^2} [/tex]
Simplify
[tex]\longrightarrow\sf \boxed{\bf t = 9.72 s} [/tex]