Respuesta :

[tex]\qquad[/tex] ☀️[tex]\pink{\bf{ {Answer = \: \: -2 }}} [/tex]

Let assume –

  • [tex] \bf (x_1,y_1) = (t,-6)[/tex]
  • [tex] \bf (x_2,y_2) = (-1,3)[/tex]

As we know – The slope formula is or the change in the y values over the change in the x values.

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf Slope, m = \dfrac{y_2-y_1}{x_2-x_1}}[/tex]

According to the question

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf \dfrac{y_2-y_1}{x_2-x_1} = 9}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf \dfrac{3 -(-6)}{-1-t}=9[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf \dfrac{3+6}{-1-t} = 9[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf \dfrac{9}{-1-t}=9[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf \dfrac{1}{-1-t} = \dfrac{9}{9}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf \dfrac{1}{-1-t} =\cancel{ \dfrac{9}{9}}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf -1-t = 1 [/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf -t = 1+1 [/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf -t = 2[/tex]

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf t = -2}[/tex]

  • Henceforth,Value of t will be -2.

answer:  When we are given 2 points, we can find the slope using those 2 points.  Now one point is missing a y-coordinate.  We use the formula for slope to find the value of r.

Slope = (y2 - y1) / (x2 - x1)

Let Point 1 = (-9, r) = (x1 , y1)

Let Point 2 = (-8, 0) = (x2 , y2)

Plug in these values into the formula for slope.  By doing so, we can get an equation that allow us to solve for r.

6 = (0 - r) / (-8 - (-9))

6 = -r / (-8 + 9)

6 = -r / 1

Multiply both sides of equation by 1.

6 = -r

Divide both sides of equation by -1.

-6 = r

pls mark me as brainliest

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