Question

Find the slope of the line that is parallel and perpendicular to the line through the pair of points (-2,-7) and (6,6) plss help pls

Answer 1

Answer:

parallel slope = $\frac{13}{8}$ , perpendicular = $\frac{-8}{13}$

Step-by-step explanation:

to find slope, formula: $\frac{y2-y1}{x2-x1}$

                                   : $\frac{6--7}{6--2}$

                                   : $\frac{13}{8}$

if parallel, same slope, so slope = 13/8

if perpendicular, slope = -1/n = -1/13/8 =  -8/13 is the perpendicular slope.