Question

A rectangle measures 10 feet by 6 feet. The length and width are each increased by 50%. What is the area of the new rectangle? Work shown with it please

Answer 1

Answer:

One hundred and thirty five

Step-by-step explanation:

fifty percent of ten is five so the new side is fifteen feet. fifty percent of six is three so that new side is nine feet. nine times fifteen is one hundred and thirty five

Answer 2

A rectangle measures 10 feet by 6 feet. The length and width are each increased by 50%. The new area of the rectangle is 135 square feet

What is the area of the rectangle?

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

A rectangle measures 10 feet by 6 feet.

The old length = 10 feet

The old width = 6 feet

The length and width are each increased by 50%.

The length increased

$0.5\times 10\\5$

The width increased

$0.5 \times 6\\3$

So, the new length = 10 + 5 = 15

the new width = 6 +3 = 9

The area of the rectangle = length × Width

= 15 x 9

= 135 square feet

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