Question

3. With a mass of 114 kg, Baby Bird is the smallest monoplane ever flown.
Suppose the Baby Bird and pilot are coasting along the runway when the pilot
jumps horizontally to the runway behind the plane. The pilot’s velocity upon
.
leaving the plane is 5.32 m/s backward. After the pilot jumps from the plane,
the plane coasts forward with a speed of 3.40 m/s. If the pilot's mass equals
60.0 kg, what is the velocity of the plane and pilot before the pilot jumps?

Answer 1

The speed of the plane and pilot before the pilot jumps is 17.8 m/s.

Conservation of linear momentum

We know that the principle of conservation of linear momentum states that the total momentum of a system is constant. This means that the momentum "before" and "after" must be equal.

Thus;

Momentum before = (114 Kg + 60.0 kg) v

Momentum after = (60.0 kg × -5.32 m/s) + (114 Kg × 3.40 m/s)

Hence;

(114 Kg + 60.0 kg) v = 3100.8

v = 3100.8/(114 + 60.0)

v = 17.8 m/s

The speed of the plane and pilot before the pilot jumps is 17.8 m/s.

Learn more about linear momentum: https://brainly.com/question/4126751