Question

Suppose 80% of people like peanut butter, 89% like jelly, and 78% like both. Given that a randomly sampled person likes peanut butter, what’s the probability that they also likes jelly?

Answer 1

Answer:

Let BB be the event that someone likes peanut butter

and let JJ be the event that someone likes jelly.

We know P(B)=0.80P(B)=0.80, P(J)=0.89P(J)=0.89 and P(B∩J)=0.78P(B∩J)=0.78.

We want to know P(J|B)P(J|B).

P(J|B)=P(J∩B)P(B)=0.780.80=0.975

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