Question

What is the temperature (in K) of 0.660 mole of neon in a 2.00 L vessel at 4.68 atm?

Answer 1

$\\ \sf\longmapsto PV=nRT$

$\\ \sf\longmapsto 4.67(2)=0.66(8.314)T$

$\\ \sf\longmapsto 9.34=5.48T$

$\\ \sf\longmapsto T=1.7°C$

• T=274.7k

Key words

• P=Pressure
• V=Volume
• n=No of moles
• R=Universal gas constant
• T=Temperature