Question

Problem 1
Bryce bought 32 stools that required assembly from Need-A-Seat. Some stools have three legs,
and the other stools have four legs. The box arrived with 108 stool legs. If the four-legged stools
cost $20 and the three-legged stools cost $15, how much did all of Bryce's stools cost? SOLVE
ALGEBRAICALLY.
2

Answer 1

The total cost of the stools is $540.

The system of equations that can be used to represent the question

a + b = 32 equation 1

3a + 4a = 108 equation 2

Where:

a = three legged stools

b = four legged stools

What is the number of three legged stools bought?

In order to determine the required value, take the following steps:

Multiply equation 1 by 3

3a + 3b = 96 equation 3

Subtract equation 3 from equation 2

b = 12

What is the number of three legged stools bought?

Substitute for b in equation 1

a + 12 = 32

a = 32 - 12

a = 20

What is the total cost of the stools?

20(15) + 20(12) =

240 + 300 = $540

To learn more about simultaneous equations, please check: https://brainly.com/question/25875552