Answer:
6
Step-by-step explanation:
[tex] log_{2}(16) + log_{2}(4) [/tex]
Remebrr that
[tex] log_{a}(b) + log_{a}(c) = log_{a}(bc) [/tex]
[tex] log_{2}(16) + log_{2}(4) = log_{2}(64) [/tex]
We get
[tex] log_{2}(64) [/tex]
[tex] = 2 {}^{x} = 64[/tex]
[tex]x = 6[/tex]
