Question

please helppppppppppppp
A net force of 15N acts upon a body of mass 3kg for 5s, calculate the change in the speed of the body​

Answer 1

• Force, F = 15 N
• Mass,m = 3 kg
• Time taken, t = 5 sec
• (v-u) =?

As we know –

$\qquad$$\purple{\bf \twoheadrightarrow F = m a }$

$\qquad$$\bf \twoheadrightarrow F = m \dfrac{ v-u}{t}$

$\qquad$$\sf \twoheadrightarrow 15 = 3 \times \dfrac{v-u}{5}$

$\qquad$$\sf \twoheadrightarrow 3 \times \dfrac{v-u}{5} = 15$

$\qquad$$\sf \twoheadrightarrow \dfrac{3}{5} \times (v-u) = 15$

$\qquad$$\sf \twoheadrightarrow (v-u)= 15 \times \dfrac{5}{3}$

$\qquad$$\sf \twoheadrightarrow (v-u)= \cancel{15} \times \dfrac{5}{\cancel{3}}$

$\qquad$$\sf \twoheadrightarrow v-u = 5 \times 5$

$\qquad$$\purple{\bf \twoheadrightarrow v-u = 25 }$

• Henceforth, the change in the speed of the body is 25 m/s.