Respuesta :
This problem cannot satisfy the triangle inequality. The triangle cannot be constructed and therefore solved.
a = 35
b = 2
c = 6
b+c ≤ a
2 + 6 ≤ 35
41 ≤ 35
The sum of the lengths of sides b, c must be greater than the length of the remaining side a.
Answer:
[tex]a=1.749[/tex]
Step-by-step explanation:
Recall Law of Sines
[tex]\frac{sin(A)}{a}=\frac{sin(B)}{b}=\frac{sin(C)}{c}[/tex]
Solve for angle B
[tex]A^\circ+B^\circ+C^\circ=180^\circ\\35^\circ+B^\circ+6^\circ=180^\circ\\41^\circ+B^\circ=180^\circ\\B^\circ=139^\circ[/tex]
Determine side "a" given angle B and side "b"
[tex]\frac{sin(35)^\circ}{a}=\frac{sin(139^\circ)}{2}\\ asin(139^\circ)=2sin(35^\circ)\\a=\frac{2sin(35^\circ)}{sin(139^\circ)}\\ a\approx1.749[/tex]
