Precalc help pls!
I’ve tried literally everything so pls help me

h(t)= t² -2t
h(x-5) = (x-5)²- 2(x-5)
= x² - 10x + 25 -2x +10
x² -12x +35
[tex]h(t)=t^2-2t\qquad \qquad h(x-5)=(x-5)^2-2(x-5) \\\\\\ h(x-5)=(x-5)(x-5)-2x+10 \\\\\\ h(x-5)=\stackrel{F~O~I~L}{(x^2-10x+25)}-2x+10 \implies h(x-5)=x^2-12x+35[/tex]