Answer:
[tex]3\sqrt{2}[/tex] units
Step-by-step explanation:
To find the distance between two points on a graph, we use the distance formula [tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2[/tex] where [tex]d[/tex] is the distance between points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex].
For this problem, we will identify [tex](x_1,y_1)\rightarrow(6,6)[/tex] and [tex](x_2,y_2)\rightarrow(3,9)[/tex]:
[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\d=\sqrt{(9-6)^2+(3-6)^2}\\\\d=\sqrt{(3)^2+(-3)^2}\\\\d=\sqrt{9+9}\\\\d=\sqrt{18}\\\\d=3\sqrt{2}[/tex]
Therefore, the distance between [tex](6,6)[/tex] and [tex](3,9)[/tex] is [tex]3\sqrt{2}[/tex] units