Question

Help me 30 points!
A 26.8 kg box sits on a ramp which is set at an angled of 13° above the horizontal. If the coefficient of static friction between the box and the ramp is 0.215, what minimum applied force is required to keep the box at rest?​

Answer 1

The minimum applied force that will keep the box at rest is 55 N.

What is frictional force?

The term frictional force refers to the force that opposes the motion of a body. We have the following information'

• Mass of the body = 26.8 kg
• angle of inclination = 13°
• coefficient of friction = 0.215

Given that;

μ = F/R

• μ = coefficient of friction
• F = frictional force
• R = reaction

R = mgcosθ = 26.8 kg × 9.8 ms-2 × cos13 =255.9 N

F = μR

F =  0.215 × 255.9 N

F = 55 N

The minimum applied force that will keep the box at rest is 55 N.

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