Please help on this math question!!

Answer:
x = 49
Step-by-step explanation:
The third side of the largest of the inner triangles:
= [tex]\sqrt{(7\sqrt{(33)^{2} }- (33)^{2}[/tex]
=[tex]\sqrt{528} =\sqrt{(16)(33)} =4\sqrt{33}[/tex]
The side that continues next to 33: x -33
Applying similarity property on right triangles:
[tex]\frac{33}{4\sqrt{33} } =\frac{4\sqrt{33} }{x-33}[/tex]
[tex](33)(x-33)=(4\sqrt{33} )^{2}[/tex]
[tex]33x-1089=528[/tex]
[tex]33x=528+1089[/tex]
[tex]x=\frac{528+1089}{33} =49[/tex]
Hope this helps