Question

Please help

What is the acceleration (in m/s squared) of the 100 kg water bucket when you apply 100 newtons of force?

What is the acceleration (in m/s squared) of a 40 kg mass when you apply 60 newtons of force?

What is the amount of force needed (in N) to accelerate a 200 kg mass to 0.50 m/s squared?

What is the force (in N) needed to accelerate 250 kg to 0.75 m/s squared?

How much force (in N) is needed to accelerate 140 kg to 2 m/s squared?

Answer 1

This question involves the concept of Newton's Second Law of Motion.

a) The acceleration is "1 m/s²".

b) The acceleration is "1.5 m/s²".

c) The amount of force needed is "100 N".

d) The force needed is "187.5 N".

e) The force needed is "280 N".

NEWTON'S SECOND LAW OF MOTION:

According to Newton's Second Law of motion whenever an unbalanced force is applied on an object, it produces an acceleration in the object in the direction of the force itself.

Mathematically,

$F = ma$

where,

• F = Applied Force
• m = mass of the object
• a = acceleration

a)

Here,

• F = 100 N

• m = 100 kg

• a = ?

Therefore,

$a=\frac{F}{m}=\frac{100\ N}{100\ kg}$

a = 1 m/s²

b)

Here,

• F = 60 N

• m = 40 kg

• a = ?

Therefore,

$a=\frac{F}{m}=\frac{60\ N}{40\ kg}$

a = 1.5 m/s²

c)

Here,

• F = ?
• m = 200 kg

• a = 0.5 m/s²

Therefore,

$F=ma = (200\ kg)(0.5\ m/s^2)$

a = 100 N

d)

Here,

• F = ?
• m = 250 kg

• a = 0.75 m/s²

Therefore,

$F=ma = (250\ kg)(0.75\ m/s^2)$

a = 187.5 N

e)

Here,

• F = ?
• m = 140 kg

• a = 2 m/s²

Therefore,

$F=ma = (140\ kg)(2\ m/s^2)$

a = 280 N

Learn more about Newton's Second Law of motion here:

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