The molar concentration of the solution is determined by the moles and the volume. The molarity of 9.82 grams of lead (IV) nitrate dissolved in 465 mL solution is 0.0464 M.
What is molarity?
Molarity is said to be the concentration of the moles dissolved in a liter of solution. It decreases with an increase in volume and is inversely proportional to it.
The molarity is calculated as,
Molarity = moles ÷ Volume
Given,
Mass of lead (IV) nitrate = 9.82 grams
The molar mass of lead (IV) nitrate = 455.2196 gm/mol
Volume of solution = 465 mL = 0.465 L
First, the moles of lead (IV) nitrate is calculated as,
Moles = mass ÷ molar mass
= 9.82 grams ÷ 455.2196 gm/mol
= 0.02157 moles
Now substituting values of moles and volume in the formula of molarity as,
M = moles (n) ÷ Volume (V)
M = 0.02157 ÷ 0.465
= 0.0464 M
Therefore, 9.82 grams of lead (IV) nitrate has a molar concentration of 0.0464 M.
Learn more about molarity here:
https://brainly.com/question/15406534
#SPJ5
