Answer:
a) 0.133 mol
b) 5.87 g
Explanation:
a)
To find the number of moles, we use the formula [tex]n=\frac{m}{M_{r} }[/tex], where m is the mass of the given substance in g, and Mᵣ is the relative molecular mass of the substance. Hence,
n of C = [tex]\frac{1.6}{12}[/tex] = [tex]\frac{2}{15}[/tex] mol = 0.133 mol (3sf)
b)
Molar ratio of C to CO₂ is 1:1. As such, for every 0.133 mol of C used, 0.133 mol of CO₂ is produced. Using the formula [tex]m=n*M_{r}[/tex],
m of CO₂ = [tex]\frac{2}{15}[/tex] × (12 + 2(16))
= [tex]\frac{2}{15}[/tex] × 44
= [tex]\frac{88}{15}[/tex] g
= 5.87 g (3sf)
