[tex]\huge\fbox{Answer ☘}[/tex]
[tex]part \: of \: field \: \: grazed \: by \: 10 \: goats \\ in \: 1 \: day = \frac{1}{32} \\ \\ part \: of \: field \: grazed \: by \: 1 \: goat \: im \: \\ 1 \: day = \frac{1}{32 \times 10} = \frac{1}{320} \\ \\ now... \: 12g = 10s \\ (g = goats) \: \\ (s = sheeps )\\ \\ 12g = 10s \\ = > g = \frac{10}{12}s \\ \\ now.. \\ 10g + 4s = 10 (\frac{10}{12})s + 4s \\ \\ = > \frac{100s}{12} + 4s \\ \\ taking \: l.c.m... \\ \\ = > \frac{100s + 48s}{12} = \frac{148s}{12} [/tex]
=> 10g + 4s ≈ 12 goats
12 goats can graze the field in
[tex] = > \frac{1}{12/320} ≈ 27 \: days \\ [/tex]
hope helpful~
