Question

b. 60 = 7 - 2y
40 + y = 4

Answer 1

Answer:

($\frac{1}{2}$, 2 )

Step-by-step explanation:

6x = 7 - 2y → (1)

4x + y = 4 ( subtract 4x from both sides )

y = 4 - 4x → (2)

substitute y = 4 - 4x into (1)

6x = 7 - 2(4 - 4x) ← distribute and simplify

6x = 7 - 8 + 8x

6x = - 1 + 8x ( subtract 8x from both sides )

- 2x = - 1 ( divide both sides by - 2 )

x = $\frac{1}{2}$

substitute this value into (2)

y = 4 - 4($\frac{1}{2}$ ) = 4 - 2 = 2

solution is ( $\frac{1}{2}$, 2 )

Answer 2

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

The given equations are ~

$\sf \: 6x + 2y = 7 \: \: \: \: \: \: \: (1)$

and

$\sf \: 4x + y = 4 \: \: \: \: \: \: \: \: \: (2)$

Now, let's simplify equation 2 for y

$\sf \: y = 4 - 4x \: \: \: \: \: \: \: \: \: \: (2)$

Plug the given value of y in equation 1st ;

$\qquad \sf  \dashrightarrow \: 6x + 2y = 7$

$\qquad \sf  \dashrightarrow \: 6x + 2(4 - 4x) = 7$

$\qquad \sf  \dashrightarrow \: 6x + 8 - 8x = 7$

$\qquad \sf  \dashrightarrow \: - 2x = 7 - 8$

$\qquad \sf  \dashrightarrow \: x = ( - 1) \div ( - 2)$

$\qquad \sf  \dashrightarrow \: \therefore \: x = \dfrac{1}{2}$

Now, use this value of x in equation 2nd to find the value of y ;

$\qquad \sf  \dashrightarrow \: y = 4 - 4x$

$\qquad \sf  \dashrightarrow \: y = 4 - (4 \times \frac{1}{2} )$

$\qquad \sf  \dashrightarrow \: y = 4 - 2$

$\qquad \sf  \dashrightarrow \: y = 2$

Therefore, the required values are ~

$\fbox \colorbox{black}{ \colorbox{white}{x} \:  \:  \:   \:  \:  \:  \: \: \colorbox{white}{=}  \:  \:  \:  \:  \:   + \colorbox{white}{ 1/2}}$

$\fbox \colorbox{black}{ \colorbox{white}{y} \:  \:  \:   \:  \:  \:  \: \: \colorbox{white}{=}  \:  \:  \:  \:  \:   + \colorbox{white}{2 \: \: \: \: }}$