The ratio of the gravitational force by earth on satellite 2 to the gravitational force by earth in satellite 1 is 3/2
This states that the gravitational force of attraction, F between two masses m₁ and m₂ is directly proportional to the product of their masses and inversely proportional to the square of their distance apart, r.
So, F = Gm₁m₂/r² where G = universal gravitational constant = 6.67 10⁻¹¹ Nm²/kg²
Now, for Satellite 1 with mass M₁ and at a distance r₁ from the earth, the gravitational force of attraction between the earth of mass M and the satellite is
F₁ = GMM₁/r₁²
Also, for Satellite 2 with mass M₂ = 6M₁ and at a distance r₂ = 2r₁ from the earh, the gravitational force of attraction between the earth of mass M and the satellite is
F₂ = GMM₂/r₂²
F₂ = GM6M₁/(2r₁)²
F₂ = 6GMM₁/4r₁²
So, the ratio of the gravitational force by earth on satellite 2 to the gravitational force by earth in satellite 1 is
F₂/F₁ = 6GMM₁/4r₁² ÷ GMM₁/r₁²
F₂/F₁ = 6/4
F₂/F₁ = 3/2
So, the ratio of the gravitational force by earth on satellite 2 to the gravitational force by earth in satellite 1 is 3/2
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