Respuesta :

Answer:

Try checking out brainly.com/question/15095540? It looks like the same question you've asked, resulting in this "Concluding; the value of q is 6, and the missing root is x = 3."

Step-by-step explanation:

Given :

  • One root of the equation x² – 5x + q = 0 is -2, then find the other root and the value of the coefficient q.

Understanding the question :

  • Here, In this question, it is given the root of the equation which means we have the value of x.
  • Now we are to put the value of x which is (-2) and by evaluating it we could find the value of q.

Solution :

[tex]\\ \qquad\sf \: \dashrightarrow \: {x}^{2} - 5x + q = 0[/tex]

Now putting the value of x in the equation :

[tex]\\ \qquad\sf \: \dashrightarrow \: {(2)}^{2} - 5(2)+ q = 0[/tex]

[tex]\\ \qquad\sf \: \dashrightarrow \: {4} - 10+ q = 0[/tex]

[tex]\\ \qquad\sf \: \dashrightarrow \: - 6+ q = 0[/tex]

[tex]\\ \qquad\sf \: \dashrightarrow \: q = 6[/tex]

Therefore, The value of coefficient q is 6 .

So, Now the equation will be :

[tex]\qquad\sf \: \dashrightarrow \: {x}^{2} - 5x + 6 = 0[/tex]

By Factorising it we get :

[tex]\\ \qquad\sf \: \dashrightarrow \: {x}^{2} - 3x - 2x + 6 = 0[/tex]

[tex]\\ \qquad\sf \: \dashrightarrow \: {x}(x - 3) - 2(x - 3) = 0[/tex]

[tex]\\ \qquad\sf \: \dashrightarrow \: (x - 3)(x - 2)= 0[/tex]

[tex]\\ \qquad\sf \: \dashrightarrow \: x =3 ,x = 2 [/tex]

Therefore, The other root is 3.

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