Question

How many moles in 49.8 Liters of O, at STP?

Answer 1

Answer:

               2.22 mole

Explanation:

At STP one mole of an ideal gas occupies 22.4 L of volume.

Hence,

Volume = mol × 22.4 L/mol

solving for mole,

Mole = Volume / 22.4 L/mol

Putting values,

Mole = 49.8 L / 22.4 L/mol

Mole = 2.22 mole