Answer:
[tex]2 \sqrt{13} [/tex]
Step-by-step explanation:
Use the pythagorean theorem
[tex] {a}^{2} + {b}^{2} = {c}^{2} [/tex]
[tex]{4}^{2} + {6}^{2} = {c}^{2} [/tex]
[tex]52 = {c}^{2} [/tex]
[tex]c = \sqrt{52} [/tex]
[tex]c = \sqrt{13 \times 2 \times 2} [/tex]
[tex]c = 2 \sqrt{13} [/tex]
