Question

As represented in the diagram below, block A with a mass of 100 grams slides to the right at 4.0
meters per second and hits stationary block B with a mass of 150 grams. After the collision, block B
slides to the right and block A rebounds to the left at 1.5 meters per second. (Neglect friction]
Before collision
After collision
Block A
Block B
Block A
Block B
m = 100.9
m - 150.0
m=100.9 m = 150.0
A
4.0 m/s
1.5 m/el
A
B
-
Calculate the speed of block Baner the collision (Show all calculations, including the equation and
substitution with units

Answer 1

We have that the  the speed of block Baner  is mathematically given as

vb=3.667m/s

Right

Mass and Speed

Mass of an object is defined as a body of matter that takes up as specific space calculated in Kg.

Speed:This is defined as the rate at which a body moves in certain direction.

Generally the equation for the Conservation law  is mathematically given as

$ma'va'+mb'vb'=mavamvvb\\\\Therefore\\\\vb=\frac{100*4+150*0-(100*(-1.5))}{150}\\\\vb=\frac{550}{150}$

• vb=3.667m/s
• Right

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