Question

One angle is twice as large as the smallest angle of a triangle. Another angle is 16 degrees larger than the
smallest angle. Find the measures of all three angles of the triangle, listing them from smallest to largest.
degrees.

Answer 1

Answer:

• The smallest angle is 41

• The second angle is 57

• The third angle is 2*41 = 82

• Step-by-step explanation:

Givens

• Let the smallest angle = x

• The second angle is x + 16

• The third angle is 2x

• The total is 180o because all triangles have 180 degrees.

Solution

• x + x + 16 + 2x = 180

• 4x + 16 = 180                Subtract 16

• 4x = 180 - 16

• 4x = 164                         Divide both sides by 4

• 4x/4 = 164/4

• x = 41