Answer:
No.
Step-by-step explanation:
1) if the given line passing through the points (-4;3)&(6;-2) is line a, and the another given line is b, then
2) it needed to compare the slopes of a and b:
[tex]slope(a)=\frac{-2-3}{6+4}=\frac{-1}{2};[/tex]
[tex]slope(b)=\frac{4-6}{-2+6}=\frac{-1}{2};[/tex]
3) if slope(a)=slope(b), then the given lines a and b are parallel (no intersections).