Answer:
10.08
Step-by-step explanation:
In [tex]\triangle ABC,\: m\angle ACB =90\degree [/tex]
[tex]\implies \triangle ABC [/tex] is a right triangle, in which side AB is hypotenuse and sides AC and BC are mutually perpendicular.
By using Pythagoras theorem:
[tex]AC^2 = AB^2 - BC^2 \\ \\ = {(11)}^{2} - {(4.4)}^{2} \\ \\ = 121 - 19.36 \\ \\ = 101.64 \\ \\ \implies \: AC= \sqrt{101.64} \\ \\ \huge\implies \: \red{AC=10.08}[/tex]
