Question

The Sum Of Three Consecutive Odd Integers Is 141. What Are They ?

Answer 1

x - the first integer
x+2 - the second integer
x+4 - the third integer

$x+x+2+x+4=141 \\ 3x+6=141 \\ 3x=141-6 \\ 3x=135 \\ x=\frac{135}{3} \\ x=45 \\ \\ x+2=45+2=47 \\ x+4=45+4=49$

The integers are: 45, 47, 49.

Answer 2

The integers are: 45, 47, 49.

Answer:

Step-by-step explanation: