Question

Write an equation in slope-intercept form for the line described.

slope −2, passes through (−4, 6)

Answer 1

Answer:

Use the slope −2 and the point (−4,−5) to find the y-intercept.

y=mx+b

⇒−5=(−2×−4)+b

⇒−5=8+b

⇒b=−13

Write the equation in slope intercept form as:

y=mx+b

⇒y=(−2)x−13

Hence, the equation of the line is y=−2x−13.

Answer 2

The linear equation in slope-intercept form is y = -2x -2

The slope of the line is given as:

m = -2

The points are given as:

(x1, y1) = (-4,6)

The linear equation in slope intercept form is:

$y = m(x -x_1) + y_1$

So, we have:

$y = -2(x +4) + 6$

Open the bracket

$y = -2x -8 + 6$

$y = -2x -2$

Hence, the linear equation in slope-intercept form is y = -2x -2

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